试题与答案

设定义在R上的函数f(x)=a0x4+a1x3+a2x2+a3x+a4,a0,a

题型:解答题

题目:

设定义在R上的函数f(x)=a0x4+a1x3+a2x2+a3x+a4,a0,a1,a2,a3,a4∈R,当x=-1时,f(x)取得极大值
2
3
,且函数y=f(x+1)的图象关于点(-1,0)对称.
(Ⅰ)求f(x)的表达式;
(Ⅱ)在函数y=f(x)的图象上是否存在两点,使以这两点为切点的切线互相垂直,且切点的横坐标都在[-
2
2
]
上?如果存在,求出点的坐标;如果不存在,请说明理由;
(Ⅲ)设xn=
2n-1
2n
,  ym=
2
(1-3m)
3m
(m,n∈N*)
,求证:|f(xn)-f(ym)|<
4
3

答案:

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参考答案:B

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