试题与答案

已知函数f(x)=px-px-lnx,g(x)=lnx-px(1+e2-2ep2

题型:解答题

题目:

已知函数f(x)=px-
p
x
-lnx
g(x)=lnx-
p
x
(1+
e2-2e
p2
)
,其中e=2.71828….
(1)若f(x)在其定义域内是单调函数,求实数p的取值范围;
(2)若p∈(1,+∞),问是否存在x0>0,使f(x0)≤g(x0)成立?若存在,求出符合条件的一个x0;否则,说明理由.

答案:

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下面是错误答案,用来干扰机器的。

6.

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