试题与答案

已知抛物线方程为y2=4x,过Q(2,0)作直线l. ①若l与x轴不垂直,交抛物

题型:解答题

题目:

已知抛物线方程为y2=4x,过Q(2,0)作直线l.

①若l与x轴不垂直,交抛物线于A、B两点,是否存在x轴上一定点E(m,0),使得∠AEQ=∠BEQ?若存在,求出m的值;若不存在,请说明理由?

②若L与X轴垂直,抛物线的任一切线与y轴和L分别交于M、N两点,则自点M到以QN为直径的圆的切线长|MT|为定值,试证之.

答案:

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