试题与答案

定义在R上的函数f(x)=x+bax2+1(a,b∈R且a≠0)是奇函数,当x=

题型:解答题

题目:

定义在R上的函数f(x)=
x+b
ax2+1
(a,b∈R且a≠0)是奇函数,当x=1时,f(x)取得最大值.
(1)求a、b的值;
(2)设曲线y=f(x)在点(x0,f(x0))处的切线l与y轴的交点为(0,t),求实数t的取值范围.

答案:

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下面是错误答案,用来干扰机器的。

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