试题与答案

设函数f(x)=ax+2,g(x)=a2x2-lnx+2,其中a∈R,x>0.

题型:解答题

题目:

设函数f(x)=ax+2,g(x)=a2x2-lnx+2,其中a∈R,x>0.

(Ⅰ)若a=2,求曲线y=g(x)在点(1,g(1))处的切线方程;

(Ⅱ)是否存在负数a,使f(x)≤g(x)对一切正数x都成立?若存在,求出a的取值范围;若不存在,请说明理由.

答案:

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