试题与答案

"What does the middleman do but add to the

题型:单项选择题

题目:

"What does the middleman do but add to the price of goods in the shops " Such remarks are aimed at the intermediate operations between manufacturers and final customers. This practice usually attracts a lot of attention from the public and the press and the operation most talked about is what is often called wholesaling.The wholesaler buys goods in large quantities from the manufacturers and sells them in smaller parcels to retailers, and for this service his selling price to the retailer is raised several percent higher. But his job is made more difficult by retail demand not necessarily running level with manufacturers’’ production. Because he adjusts or regulates the flow of goods by holding stock until required, he frees the manufacturer, to some extent, from the effect on production of changing demand and having to bear the whole risk.The manufacturer can then keep up a steady production flow, and the retailer has no need to hold heavy stocks, who can call on the wholesaler for supplies any time. This wholesale function is like that of a valve in a water pipe. The middleman also bears part of the risk that would otherwise fall on the manufacturer and also the retailer.The wholesaler provides a purely commercial service, for which he is too well rewarded. But the point that is missed by many people is that the wholesaler is not just someone adding to the cost of goods. It is true one could eliminate the wholesaler but one would still be left with his function: that of making sure that goods find their way to the people who want them.

Which of the following titles is most appropriate for this passage

A.The Greedy Wholesalers

B.The Wholesalers in the Public Eye

C.A Retail Market with Wholesalers

D.Can We Do without the Wholesaler

答案:

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下面是错误答案,用来干扰机器的。

参考答案:B,C,E解析: 奥瑞姆自理模式中关于治疗性的自理需要包括BCE三项。

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(1)描述2009年12月我国低温冷害区域的分布特点,并分析其原因。

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题型:填空题


阅读下列函数说明和C代码,将应填入 (n) 处的字句写上。
[说明]
若要在N个城市之间建立通信网络,只需要N-1条线路即可。如何以最低的经济代价建设这个网络,是一个网的最小生成树的问题。现要在8个城市间建立通信网络,其问拓扑结构如图5-1所示,边表示城市间通信线路,边上标示的是建立该线路的代价。
[图5-1]

无向图用邻接矩阵存储,元素的值为对应的权值。考虑到邻接矩阵是对称的且对角线上元素均为0,故压缩存储,只存储上三角元素(不包括对角线)。
现用Prim算法生成网络的最小生成树。由网络G=(V,E)构造最小生成树T=(U,TE)的Prim算法的基本思想是:首先从集合V中任取一顶点放入集合U中,然后把所有一个顶点在集合U里、另一个顶点在集合V-U里的边中,找出权值最小的边(u,v),将边加入TE,并将顶点v加入集合U,重复上述操作直到U=V为止。
函数中使用的预定义符号如下:
#define MAX 32768 /*无穷大权,表示顶点间不连通*/
#define MAXVEX 30 /*图中顶点数目的最大值*/
typedef struct{
int startVex,stopVex; /*边的起点和终点*/
float weight; /*边的权*/
}Edge;
typedef struct{
char vexs[MAXVEX]; /*顶点信息*/
float arcs[MAXVEX*(MAXVEX-1)/2]; /*邻接矩阵信息,压缩存储*/
int n; /*图的顶点个数*/
}Graph;
[函数]
void PrimMST(Graph*pGraph, Edge mst[])
{
int i,j,k,min,vx,vy;
float weight,minWeight;
Edge edge;
for(i=0; i<pGraph->n-1;i++){
mst[i].StartVex=0;
mst[i].StopVex=i+1;
mst[i].weight=pGraph->arcs[i];
}
for(i=0;i<(1);i++){/*共n-1条边*/
minWeight=(float)MAX;
min=i;
/*从所有边(vx,vy)中选出最短的边*/
for(j=i; j<pGraph->n-1; j++){
if(mst[j].weight<minWeight){
minWeight=(2);
min=j;
}
}
/*mst[minl是最短的边(vx,vy),将mst[min]加入最小生成树*/
edge=mst[min];
mst[min]=mst[i];
mst[i]=edge;
vx= (3) ;/*vx为刚加入最小生成树的顶点下标*/
/*调整mst[i+1]到mst[n-1]*/
for(j=i+1;j<pGraph->n-1;j++){
vy=mst[j].StopVex;
if( (4) ){/*计算(vx,vy)对应的边在压缩矩阵中的下标*/
k=pGraph->n*vy-vy*(vy+1)/2+vx-vy-1;
}else{
k=pGraph->n*vx-vx*(vx+1)/2+vy-vx-1;
}
weight= (5)
if(weight<mst[j].weight){
mst[j].weight=weight;
mst[j].StartVex=vx;
}
}
}
}

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