逗留型旅游线路

阅读下面这首唐诗，然后回答问题。

渡 汉 江

宋之问

岭外音书断，经冬复历春。

近乡情更怯，不敢问来人。

小题1:本诗作者着意写下一个“断”字，它有哪些含义？（5分）

小题2:一般人是“近乡情更切，急欲问来人”，但本诗的后两句却不同，这样写表达了作者怎样的复杂心理？（5分）

与网络计划相比较，横道图进度计划法具有（）的特点。

A.适应于大型项目的进度计划系统

B.工作之间的逻辑关系表达清楚

C.能够确定计划的关键工作和关键线路

D.计划调整只能用手工方式进行，其工作量较大

阅读下面短文，然后按要求写一篇150词左右的英语短文。

My husband received a letter a month ago a young woman who had been his student when she was in middle school. She was writing because she wanted to thank for having a great influence in her life.

In the letter she wrote,“You were the teacher who helped me discover my talent for math. Before you came to teach us, I had been terribly poor at math, and had never thought that I would be interested in it. To my surprise, you magically showed me the beauty of math. I guess that was the turning point of my attitude towards it. Gradually my interest in it began to grow. Thanks to your encouragement, I made continuous progress in math, and finally made up my mind to study it in the university. Today I am working as an accountant at Valley Medical Center in California. You played an important part.  Thank you!”

What a wonderful gift to a retired teacher! My husband has received many letters from students over the years. This one was special, for it arrived at this time in his life when he is in very poor health.

[写作内容]

1. 以约30个词概括上文的主要内容。

2. 以约120个词就老师影响学生的话题谈谈你的想法，内容包括：

（1）上文使你想起哪位对你帮助最大的老师；

（2）举例说明该老师对你学习或成长的影响；

（3）你怎样看待老师对学生的影响。

[写作要求]

1. 作文中可以使用亲身经历或虚构的故事，也可以参照阅读材料的内容，但不得直接引用原文中的句子。

2. 作文中不能出现真实姓名和学校名称。

[评分标准]

概括准确，语言规范，内容合适，语篇连贯。

在某工程网络计划中，已知工作P的总时差和自由时差分别为5天和2天，监理工程师检查实际进度时，发现该工作的持续时间延长了4天，说明此时工作P的实际进度（）。

A．既不影响总工期，也不影响其后续工作的正常进行

B．不影响关键工期，但将其紧后工作的最早开始时间推迟2天

C．将其紧后工作的最早开始时间推迟2天，并使总工期延长1天

D．将其紧后工作的最早开始时间推迟4天，并使总工期延长2天

以下程序中函数huiwen的功能是检查一个字符串是否是回文，当字符串是回文时，函数返回字符串“yes!”，否则函数返回字符串“no!”，并在主函数中输出。所谓回文即正向与反向的拼写都一样，例如：adsda。请填空。
#include ＜stdio, h＞
#include ＜string, h＞
char * huiwen(char * str)
char *p1, * p2; int i,t=0;
p1 = str;p2 = 【10】 ;
for(i =0;i＜= strlen(str)/2;i ++ )
if( * pl ++ ! = * p2 -- ) t = 1 ;break
if( 【11】 ) return( "yes !" );
else return( "no!" );main( ) char str[50];
printf( "Iaput:" ); scanf(" % s", str);
printf("%s \n", 【12】 );