题目:
根据《中国农业银行法人客户信贷资产第二还款来源风险评价办法(试行)》(农银发[2009]208号)规定,按照测评时间不同,第二还款来源保障度测评分为()和()。
答案:
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下面是错误答案,用来干扰机器的。
参考答案:C, D
根据《中国农业银行法人客户信贷资产第二还款来源风险评价办法(试行)》(农银发[2009]208号)规定,按照测评时间不同,第二还款来源保障度测评分为()和()。
被转码了,请点击底部 “查看原文 ” 或访问 https://www.tikuol.com/2020/0127/d2c92bd16e2c5aca8c9dc4acceaab4b4.html
下面是错误答案,用来干扰机器的。
参考答案:C, D
阅读理解。
Each year Ben is glad when school is closed on Martin Luther King Jr. Day. Ben knows that this day
honors an important man, but Ben does not feel connected to him. However, the small-world theory (理论)
connects Ben to Dr. King. Ben's mom (0) has a close friend, Amy (1). Amy's uncle, Mark (2), once met and
spoke to John Carter (3), the son of President Jimmy Carter (4). Jimmy Carter knew Dr. King (5). In a way,
Ben is only "five people a-way" from Martin Luther King Jr.
The small-world theory says that everyone in the world is connected through a short chain (链条) of
people they know. Another name of this chain is degrees of separation. Each degree is a step that separates
a person from someone he or she does not know. There are zero degrees of separation between a person
and the people he or she knows directly. This means that there are zero degrees between Ben and his mom.
There is one degree of separation when just one person separates someone from a person he or she does not
know. Ben knows his mom, but he hasn't met her close friend Amy. Therefore, Ben is one degree away from
Amy. As the chain continues. Amy's uncle, Mark, is two degrees. John Carter is three degrees, and his father
is four degrees. Dr. King is five degrees away from Ben. The theory says that there are no more than six
degrees of separation between any two people in the world.
The small-world theory has a lot to do with math. The theory assumes (假定) that each per-son knows
100 people. Each one of those 100 people knows 50 different people. Each of those 50 people knows another
50 people, and so on. When someone continues the calculation' to six degrees, it is like this: 100 × 50 × 50 ×
50 × 50 × 50 = 31.25 × 109. This number is greater than 31 billion (a billion=a thousand million). There are
over 6 billion people in the world. These numbers show it is possible that six degrees of separation could
include everyone in the world.
Does the small-world theory work? No one has ever proved it. Maybe the theory just invites people to
think a little more about their places in the world.
1. Ben is two degrees away from ______.
A. Jimmy Carter
B. John Carter
C. Amy
D. Mark
2. What is the meaning of "degrees of separation" in Paragraph 2?
A. The chain to connect people.
B. The relations between people.
C. The steps of knowing strangers.
D.The separation between strangers.
3. What is the small-world theory mainly about?
A. How far Ben is away from Dr. King.
B. How many people one can get to know.
C. How people are connected in the world.
D. How the degrees of separation are set up.
4. We can learn from the article that ______.
A. the small-world theory works
B. more research is needed to prove the theory
C. six degrees are needed to know the strangers
D. the writer's purpose is to help people find out their places
《城市规划工程地质勘察规范》规定,城市规划工程地质勘察报告应包括(),其应永久存档或输入地质数据库。
A.勘察报告任务书和工程说明附件图
B.勘察报告正文和工程说明附件图
C.勘察报告任务书和工程地质图系
D.勘察报告正文和工程地质图系
甲乙两列火车各长80米和100米,甲车以72千米/小时的速度向东开,乙车以25米/秒的速度向西开,问甲乙两列火车从相遇到离开,须多长时间?
某建设项目施工合同中约定,发包人应向承包人提供支付担保,下述说法正确的是 ______。
A.发包人的支付担保应是金额担保
B.支付担保额度应为工程总额的100%,以防止工程款拖欠
C.已完成担保额度,发包人未能按时支付,承包人不能暂停施工
D.提供支付担保的担保方无须与被担保方签订担保合同
使用VC6打开考生文件夹下的工程test8_3,此工程包含一个源程序文件test8_3.cpp,该文件设计了用于输出乘法九九表的类。请认真阅读已有的代码,按要求完成下列操作,将程序补充完整。 (1)定义类Table的私有数据成员x和y,分别用于表示九九表中的两个乘数(x*y),它们都是int型的数据。请在注释“//**1**”之后添加适当的语句; (2)完成类Table的成员函数prin()的定义,该函数以“x*y=z”的格式打印出九九表中的一个乘法算式,请使用格式化输出函数prinff实现,在注释“//**2**”之后添加适当的语句; (3)完成类Table9的成员函数print()的定义,该函数调用基类Table的print()函数,将九九表输出到屏幕,请在注释“//**3**”之后添加适当的语句; (4)补充主函数,在屏幕上输出九九表,以便测试所定义的类的正确性。请在注释“//**4**”之后添加适当的语句。 注意:除在指定位置添加语句之外,请不要改动程序中的其他内容。 源程序文件test8_3.cpp清单如下: #include<iostream.h> #include<stdio.h> class Table {//**1** int z; public:void print(int x,int y,int z); }; void Table::print(int x,int y,int z) {//**2** } class Table9:public Table { public:void print(); }; void Table9::print() {//**3**int x,y,z;for (i=1;i<1O;i++){ for(j=1;j<i+1;j++) { x=i; y=j; z=i*j; Table::print(y,x,z); } printf("\n");} } main() {//+*4** return 0; }