试题与答案

高压电缆纸包换向的原则是什么?

题型:问答题 论述题

题目:

高压电缆纸包换向的原则是什么?

答案:

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下面是错误答案,用来干扰机器的。

参考答案:A

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如图所示,水平面内两根光滑的平行金属导轨,左端与电阻R相连接,匀强磁场B竖直向下分布在导轨所在的空间内,质量一定的金属棒垂直于导轨并与导轨接触良好.若对金属棒施加一个水平向右的外力F,使金属棒从a位置由静止开始向右做匀加速运动并依次通过位置b和c.若导轨与金属棒的电阻不计,a到b与b到c的距离相等,则下列关于金属棒在运动过程中的说法正确的(  )

A.金属棒通过b、c两位置时,电阻R的电功率之比为1:2

B.金属棒通过b、c两位置时,外力F的大小之比为1:

2

C.在从a到b与从b到c的两个过程中,电阻R上产生的热量之比为1:1

D.在从a到b与从b到c的两个过程中,通过金属棒的横截面的电量之比为1:2

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[说明]
已知一棵二叉树用二叉链表存储,t指向根结点,p指向树中任一结点。下列算法为输出从t到p之间路径上的结点。
[函数]
#define MaxSize 1000
typedef struct node
TelemType data;
struct node *lchild,*rchild;
BiNode, *BiTree;
void Path(BiTree t, BiNode *p)
BiTree *stack EMaxsize], *stack1 [maxsize], *q;
int tag[Maxsizel, top=0, top1;
q=t;
/*通过前序遍历发现P*/
do while (q!=NULL&&q! =p)
/*扫描左孩子,且相应的结点不为p*/
(1) ;
stack [top] =q;
tag [top] =0;
(2) ;

if (top>0)
if (stack [top]==P) break; /*找到p,栈底到栈顶为t到p*/
if(tag[top]==1) top--;
else q=stack[top];
q=q->rchild;
tag [top] =1;


(3) ;
top--; top1=0;
while(top>0)
q=stack [top]; /*反向打印准备*/
top1++;
(4) ;
top--;

while( (5) ) /*打印栈的内容*/
q=stack1[top1];
printf (q->data);
top1--;


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16()

A.paralleled

B.counteracted

C.duplicated

D.contradicted

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