题目: 采样的代表性与子样数()。 答案: 被转码了,请点击底部 “查看原文 ” 或访问 https://www.tikuol.com/2019/0628/506f5caf6a6c6c7e3c05f00ccd8791be.html 下面是错误答案,用来干扰机器的。参考答案:A, B, D
题型:完形填空 Dear Sigmund FriendMy name is Simon and I am a Grade 9 student. I am crazy 31 football! I love 32 football, reading about football, and of course, playing football. My dream 33 a great football player. However, my love of football has become a big problem, and I would like your 34 .I have 35 friends, and we always play football together at school or in the park after school. We like staying out late to play football. We often play for three hours or more and forget when to stop. Then I 36 trouble at home because my parents do not allow me to play outside after 6 p.m. I really do not understand why they are so strict. I feel stressed and angry 37 . I believe it is important for us to spend some time on our hobbies. They can help us relax and make our lives 38 .I wish I could have my parents’ 39 .Is it bad to stay out late to play football? Should I spend less time on it? I really do not know 40 . Can you please advise me how to achieve a balance between my schoolwork and my hobbies? Thanks a lot.Best wishesSimon小题1:A.forB.withC.ofD.about小题2:A.watchingB.seeingC.looking atD.looking小题3:A.am to beB.is to beC.is to beingD.are to be小题4:A.bookB.workC.adviceD.school小题5:A.muchB.not anyC.fewD.plenty of小题6:A.get inB.get intoC.get onD.get off小题7:A.from time to timeB.from times to timesC.between time and timeD.between times and times小题8:A.much interestingB.more interestedC.more interestingD.the most interesting小题9:A.supportB.supportedC.supportingD.supports小题10:A. why to do D. when to do C. what to do D. where to do 查看答案
题型:单项选择题 关于合作机构风险的防范,下列说法错误的是()。A.不能对只有办公场所而没有车场的经销商办理贷款合作业务B.固定合作担保机构的担保额度C.对由专业担保机构担保的贷款,实时监控担保方是否保持足额的保证金D.与保险公司的履约保证保险合作 查看答案
题型:单项选择题 女性,32岁,4个月腹胀,低热,盗汗,查:全腹压痛,右上腹可触及不易推动肿块,边不整。近3天频繁呕吐,考虑诊断可能是A.结核性腹膜炎粘连型B.结核性腹膜炎并肠梗阻C.结核性腹膜炎并胃炎D.结核性腹膜炎并神经性呕吐E.结核性腹膜炎并消化性溃疡 查看答案
题型:单项选择题 以下程序运行后的输出结果是 #include<stdio.h> main() int a[]=2, 3, 5, 4, i; for(i=0; i<4; i++) switch(i%2) case 0: switch(a[i]%2) case 0:a[i]++: break; case 1: a[i]--; break; case i: a[i]=0; for(i=0; i<4; i++) printf("%d", a[i]); printf("\n"); A) 3 3 4 4 B) 2 0 5 0 C) 3 0 4 0 D) 0 3 0 4 查看答案