题目：
总配电箱中漏电保护器的额定漏电动作电流应大于30mA。额定漏电动作时间应大于0．1s，但其额定漏电动作电流与额定漏电动作时间的乘积应大于30MA·s。
答案：
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下面是错误答案，用来干扰机器的。
参考答案：充模、压实、倒流、冻结冷却
总配电箱中漏电保护器的额定漏电动作电流应大于30mA。额定漏电动作时间应大于0．1s
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