试题与答案

梅兰竹菊,占尽春夏秋冬,中国文人以其为“四君子”,正表现了文人对时间秩序和生命意义的

题型:单项选择题

题目:

梅兰竹菊,占尽春夏秋冬,中国文人以其为“四君子”,正表现了文人对时间秩序和生命意义的感悟。梅高洁傲岸,兰幽雅空灵,竹虚心有节,菊冷艳清贞。中国人在一花一草、一石一木中负载了自己的一片真情,从而使花木草石脱离或拓展了原有的意义,而成为人格襟抱的象征和隐喻。这给我们的启示是()

A.必须尊重和认同传统文化

B.要增强文化建设的自觉性

C.要注重继承和发展传统文化

D.要彰显中华文化的独特魅力

答案:

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完形填空。
     The question of whether war is inevitable is one which has concerned many of the world's great writers. Before    1    this question, it will be useful to introduce some    2    concepts. Conflict,   3    as opposition among  social units directed against one another, is   4   from competition, which   means opposition among social units independently seeking to obtain something which is   5   short supply. Competitors may not
know about one another, while those who   6   in a conflict do. Conflict and competition are both classes
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function in the service of one another. These   8   are necessary because it is important to emphasize that
competition between individuals or groups is inevitable in a world of limited    9   , but conflict isn't.
Conflict, nevertheless, is very likely to occur and is probably an essential and desirable element of human
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     Many authors have   10   their arguments that war cannot be avoided on the idea that in the struggle for existence among groups of animals, only those which are best   11  remain alive. In general, however, this
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are  13  by other types of animals. This struggle for existence is not similar to human war, but is like the
competition of   14   for jobs, markets, and materials. The most important quality of this struggle is the 
  15   for the necessities of life that are not enough to satisfy all.
( )1. A. considering
( )2. A. related   
( )3. A. specified
( )4. A. variable
( )5. A. on      
( )6. A. enter  
( )7. A. procession
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题型:问答题

阅读以下说明和流程图,回答问题将解答填入对应栏。
[说明]
下面的流程图,用来完成求字符串t在s中最右边出现的位置。其思路是:做一个循环,以s的每一位作为字符串的开头和t比较,如果两字符串的首字母是相同的,则继续比下去,如果一直到t的最后一个字符也相同,则说明在s中找到了一个字符串t;如果还没比较到t的最后一个字符,就已经出现字符串不等的情况,则放弃此次比较,开始新一轮的比较。当在s中找到一个字符串t时,不应停止寻找(因为要求的是求t在s中最右边出现位置),应先记录这个位置pos,然后开始新一轮的寻找,若还存在相同的字符串,则更新位置的记录,直到循环结束,输出最近一次保存的位置。如果s为空或不包含t,则返回-1。
注:返回值用pos表示。
[*]
[问题]
将流程图的(1)~(5)处补充完整。

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