试题与答案

质量为2m,半径为R的偏心圆板可绕通过中心O的轴转动,偏心距OC=R/2。在OC连线

题型:单项选择题

题目:

质量为2m,半径为R的偏心圆板可绕通过中心O的轴转动,偏心距OC=R/2。在OC连线上的A点固结一质量为m的质点,OA=R如图示。当板以角速度w绕轴O转动时,系统动量K的大小为()。(注:C为圆板的质心)。

A.K=0

B.K=mRw

C.K=3/2mRw

D.K=2mRw

答案:

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参考答案:E

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