题型:选择题 △ABC三边成等差数列且a>c>b,已知顶点A(-1,0),B(1,0),则顶点C的轨迹方程为( )A.x24+y23=1(x≠0)B.x24+y23=1(y≠0)C.x24+y23=1(x<0)D.x24+y23=1(x<0,y≠0) 查看答案