试题与答案

会议典型发言一般不超过()分钟。A.30 B.20 C.15 D.10

题型:单项选择题

题目:

会议典型发言一般不超过()分钟。

A.30

B.20

C.15

D.10

答案:

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Side A                                                                                                                                    No. 293083
          
    

                                              

Side B                                                                                                                                    No. 293083

Thank you for travelling with
If the card is fo~lnd, please return,  to any Stagecoach driver.
                                                              
1. The card is used for _____.
A. taking a taxi                          
B. travelling by train
C. taking a bus                          
D. entering the college                                                   
2. Lilian is _____.
A. a bus driver                          
B. a university student
C. a teacher in a college                  
D. a middle school student
3. The card can be used in any of the four _____.
A. cities            
B. colleges          
C. universities        
D. companies
4. According to the reading material, if you find a lost card, you can _____.
A. sell it                              
B. phone Lilian
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【程序说明】
本程序先从文件读人各考生的准考证号(设为整型数)及成绩,并将其存放在一棵检索二叉树上,二叉树结点的健值是成绩,每个结点带一链表,链表结点存放取得该成绩的考生的准考证号。然后,程序按中序遍历检索二叉树,从高分到低分输出结果,使每行输出成绩及其取得成绩的考生的准考证号。
【程序】
#include < stdio. h >
typedef struet idnode
int id;
struct idnode * next;
ldNode;
typedef struct marknode I
int mark;
ldNode * head;
struct marknode * left, * right;
MarkNode;
char fname [ ] = "sp07.dat";
main( )
int id, mark;
MarkNode * root = null;
FILE * fp = fopen(fname," r" );
if(!fp)
printf("file%s open error, \n" , fname);
exit(0);

while (!feop(fp))
fscanf(fp," %d%d", &id, &mark);
btree(&root, id, mark);

fclose(fp);
print(root);

btree(MarkNod * * mpptr, int id, int mark)
ldNode * ip;
MarkNode *mp = * mpptr;
if (1)
if (mark==p->mark) addldNODE ( (2) , id);
else if ( mark >mp -> mark) btree (&top -> left, id, mark);
else btree(&mp-> right, id, mark);
else
Imp = ( marknode * ) malloc(sizeo (marknode) );
mp -> mark = mark;
mp -> left =mp -> right = NULL;
(3)
addldNode(&mp -> head, id);
(4) ;


addldNode(ldNode * * ipp, int id)
ldNode * ip = * ipp;
if ( (5) )addldNode ( (6) ), id;
else
ip = (ldNode * )malloc(sizeof(ldNode) );
sp - > id = id;
ip -> next = NULL;
(7)


print(MarkNode * rap)
ldNode *ip, *ip0;
if (mp)
print ( mp -> left);
printf(" %6d: \t" ,mp -> mark);
ip = mp -> head;
while(ip)
printf(" %6d" ,ip -> id);
ip0 =ip;
ip = ip -> next;
free (ip0);

printf(" \n" ); printf( mp -> right); free(mp);

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