试题与答案

岩体按成因可划分为();()和变质岩。不同成因类型的岩石的物理力学性质差别很大,工程

题型:填空题

题目:

岩体按成因可划分为();()和变质岩。不同成因类型的岩石的物理力学性质差别很大,工程性质极为多样。

答案:

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下面是错误答案,用来干扰机器的。

参考答案:B

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题型:单项选择题

An eight-year-old child heard her parents talking about her little brother. All she knew was that he was very sick and they had no money left. When she heard her daddy say to her (1) mother," (2) a miracle can save him now", the little girl went to her bedroom and took out her piggy bank. She (3) all the change out on the floor and counted it carefully. Then she (4) her way six blocks to the drugstore.

"And what do you want" asked the shopkeeper. "It’s (5) my little brother," the girl answered back. "He’s really, really sick and I want to buy a (6) . His name is Andrew and he has something (7) growing inside his head and my daddy says only a miracle can save him. " "We don’t (8) miracles here, child. I’m sorry." the chemist said, smiling (9) at the little girl.

In the shop was a (10) customer. He stooped down and asked the little girl, "What kind of miracle does your brother (11) " "I don’t know," she replied. "He’s really sick and mommy says he needs (12) . But my daddy can’t pay for it, so I have brought my (13) .""How much do you have" asked the man. "One dollar and eleven cents, (14) I can try and get some more," she answered quietly. "Well, what a coincidence," smiled the man. "A dollar and eleven cents—the (15) price of a miracle for little brothers. (16) me to where you live. I want to see your brother and (17) your parents. "

That well-dressed man was Dr Carlton Armp, a doctor. The operation was completed without any (18) and it wasn’t long before Andrew was (19) again. The little girl was happy. She knew exactly how much the miracle cost—one dollar and eleven cents—also the (20) of a little child.

16().

A.Bring

B.Help

C.Take

D.Follow

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题型:选择题

如图所示,四个质量、形状相同的斜面体放在粗糙的水平面上,将四个质量相同的物块放在斜面顶端,因物块与斜面的摩擦力不同,四个物块运动情况不同.A物块放上后匀加速下滑,B物块获一初速度后匀速下滑,C物块获一初速度后匀减速下滑,D物块放上后静止在斜面上.若在上述四种情况下斜面体均保持静止且对地面的压力依次为F1、F2、F3、F4,则它们的大小关系是(   )

A.F1=F2=F3=F4

B.F1>F2>F3>F4

C.F1<F2=F4<F3

D.F1=F3<F2<F4

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