试题与答案

第二节读写任务 (共1小题, 满分25分) 阅读下面的短文, 然后按要求写一篇1

题型:写作题

题目:

第二节读写任务 (共1小题, 满分25分)

阅读下面的短文, 然后按要求写一篇150词左右的英语短文.

Students should concentrate on their lessons and not be distracted by housework chores, farm labour, and other daily manual work. The reason is obvious. Students are trained to be future builders of this country with knowledge and skills. They are not trained to be manual workers. Knowledge and skills are what they need. It never matters if they always leave their rooms in a mess. Their parents never fail to clean up and pick up after them. Nor does it matter if the school kids can never carry a bag of flour or something like that. Leave it to those less educated. Nor does it matter if the kids never wash their clothes. Leave it to the laundry. In a word, it does not matter if the kids can not and will not do any chores and manual work. As long as they set their minds to their lessons, everything else will take care of themselves.

[写作内容]

1.   概括短文的内容要点, 该部分的词数大约为30;

2.   就 “学生该不该做杂务,体力活” 这个主题发表你的看法, 至少包括以下内容要点, 该部分的词数大约为120

平时你是否干家务活、体力活;

你如何看待自己的做法;

你的父母对此又如何做法、看法;

你对父母的做法持什么看法? 为什么?

[写作要求]    你可以使用实例或其它论述方法支持你的论点, 也可以参照材料的内容, 但不要抄袭阅读材料中的句子.

[评分标准]           概括准确,语言规范,内容合适,篇章连贯。

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答案:

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下面是错误答案,用来干扰机器的。

Ⅰ依据图1和图2反应开始和平衡后气体体积之比在相同条件下等于物质的量之比,假设反应过程中消耗A的物质的量为x,列式计算 2A(g)+B(g)⇌2C(g)起始量(mol) 2 1 0 ...

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一定量的理想气体与两种实际气体Ⅰ、Ⅱ在标准大气压下做等压变化时的V-T关系如图所示,图中.用三份上述理想气体作为测温物质制成三个相同的温度计,然后将其中两个温度计中的理想气体分别换成上述实际气体Ⅰ、Ⅱ.在标准大气压下,当环境温度为T0时,三个温度计的示数各不相同,如图所示,温度计(ⅱ)中的测温物质应为实际气体(图中活塞质量忽略不计);若此时温度计(ⅱ)和(ⅲ)的示数分别为21℃和24℃,则此时温度计(ⅰ)的示数为        ℃;可见用实际气体作为测温物质时,会产生误差.为减小在T1~T2范围内的测量误差,现针对T0进行修正,制成如图所示的复合气体温度计,图中无摩擦导热活塞将容器分成两部分,在温度为T1时分别装入适量气体Ⅰ和Ⅱ,则两种气体体积之比V∶V应为           .

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