试题与答案

在双缝干涉实验中,用氦氖激光器作光源,其发出的红光频率为4.74×1014Hz,

题型:问答题

题目:

在双缝干涉实验中,用氦氖激光器作光源,其发出的红光频率为4.74×1014Hz,从双缝射出的光的振动情况完全相同,它们到达光屏上某点的路程差为2531.6nm.那么该点将出现怎样的干涉图样?

答案:

本题考查双缝干涉实验中出现明暗条纹的条件.根据光波的速度公式

c=λf

有λ=

c
f
=
3.0×108
4.74×1014
m

=0.6329×10-6m=632.9nm

光的路程差跟红光波长之比为

n=

△s
λ
=
2531.6
632.9
=4

即路程差为红光波长的整数倍.因此,两束红光在该点振动加强,出现红色的明条纹.

答:该点将出现红色的明条纹

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