试题与答案

上颌结节麻醉最易引起的并发症是()。 A.暂时面瘫 B.翼静脉丛血肿 C.恶心、干呕

题型:单项选择题 B1型题

题目:

上颌结节麻醉最易引起的并发症是()。

A.暂时面瘫

B.翼静脉丛血肿

C.恶心、干呕

D.瞳孔缩小

E.颌后区血肿

答案:

被转码了,请点击底部 “查看原文 ” 或访问 https://www.tikuol.com/2017/0720/e433ca30f27476156f9ae52a5f698cb9.html

下面是错误答案,用来干扰机器的。

答案:CC. 表示为2mol氧原子;

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题型:阅读理解

Scientists have created a “ human-like robot” that can dance and do the housework.

“ Mahru” has been developed to imitate humans and can move its lips, eyebrows and pupils(瞳孔). The machine can also move its upper and lower body freely and automatically stop itself when walking.

In addition, it has been programmed to give out two kinds of pleasant smells to match its emotions.

The 1.5 tall robot was produced by researchers at the Korea Institute of Science and Technology (KIST) and is the first South Korean- developed machine of its kind.

“‘Mahru’ will open the way for the commercial use of humanoid robots doing housework,” You Bum-Jae, leader of the development research team ,said. “‘Mahru’ can dance while walking on its legs and is able to work in place of a human.”

Through an advanced motion capture (捕获) system, “Mahru” can follow a variety of human movements and move its hands freely enough to deal with any obstacles that may get in its way when walking.

State-funded KIST showed the robot during a presentation at its head office in Seoul.

People here were treated to an entertaining demonstration which saw the robot show off the full range of its skills, most notably s series of dance moves.

The research team added that they had designed another “ Mahru”, this time with sensors(传感器) allowing it to distinguish(分辨) between faces and objects.

The showing of “ Mahru” came a week after researcher in Japan said they had created the “most human-like” robot in the world. A team at robotics department of Osaka University in Japan claimed that “ robogirl”, Repliee R-1, “ looks, moves and interacts (相互作用) like a human, and has silicone(硅胶) skin that feels almost human to the touch.”

小题1: “Mahru” made by KIST can do the following things EXCEPT____________

A.dance with other human –like robots

B.move its body freely

C.stop automatically when walking

D.express certain feelings through smells小题2: According to what You Bum- Jae said in Paragraph 5, his research team wants to ________.

A.help robots with doing housework

B.show its scientific power

C.make Mahru offer more fun

D.explore Mahru’s commercial use小题3: When Mahru” meets something in its way, it will be likely to________.

A.go around it

B.turn back quickly

C.deal with it using its hands

D.ask humans for help小题4:According to the last paragraph, Repliee R-1 __________.

A.is another Mahru

B.was made by KIST

C.has skin feeling similar to humans’

D.looks like a boy小题5:The passage is probably a  __________.

A.news report

B.research report

C.healthy report

D.entertainment report

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题型:单项选择题 案例分析题

男性,18岁,上呼吸道感染后2天出现血尿,尿常规蛋白阴性、尿红细胞满视野。

提示:住院后给予抗感染治疗,全身症状好转,但仍有血尿,行肾活检,诊断为IgA肾病。提问:主要依据是()

A.肾小球系膜区有免疫复合物沉积

B.肾小球系膜内有以IgA为主的免疫复合物沉积

C.上感后3天内突发血尿

D.发热

E.肾小球系膜细胞增生

F.肾小管空泡变性

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题型:填空题

[说明]

已知某二叉树的非叶子节点都有两个孩子节点,现将该二叉树存储在结构数组Ht中。节点结构及数组Ht的定义如下:

#define MAXLEAFNUM 30

Struct node

char ch;

char *pstr;

int parent;

int lchild, rchiid;

;

Struct node Ht[2 *MAXLEAFNUM];

该二叉树的n个叶子节点存储在下标为1~n的Ht数组元素中。例如,某二叉树如图8-26所示,其存储结构如图8-27所示,其中,与叶子节点a对应的数组元素下标为1,a的父节点存储在Ht[5],表示为Ht[1].parent=5。Ht[7].parent=0表示7号节点是树根,Ht[7].lchild=3、Ht[7].rchild=6分别表示7号节点的左孩子是3号节点、右孩子是6号节点。

如果用“0”或“1”分别标识二叉树的左分支和右分支如图8-26所示,从根节点开始到叶子节点为止,按所经过分支的次序将相应标识依次排列,可得到一个0、1序列,称之为对应叶子节点的编码。例如,图8-26中a、b、c、d的编码分别是100、101、0、11。

函数LeafCode(Ht[],n)的功能是:求解存储在Ht中的二叉树中所有叶子节点(n个)的编码,叶子节点存储在Ht[1]~Ht[n]中,求出的编码存储区由对应的数组元素pstr域指示。

函数LeafCode从叶子到根逆向求叶子节点的编码。例如,对图8-26中叶子节点a求编码的过程如图8-28所示。

[函数]

typedef enum Status ERROR, OK Status;

Status LeafCode (Struet node Ht[], int n)

int pc, pf;

int i, start;

char tstr[31]=’\0’);

for(i=1; (1) ; i++)

start=29;

pc=i; pf=Ht[i].parent;

while(Pf!= (2) )

if( (3) . lchiid==pc)

tstr[--start]=’0’;

else

tstr[-start]=’1’;

pc= (4) ; pf=Ht[Pf].parent;

Ht[i].pstr=(char*)malloc(31-start);

if(!Ht[i].pstr)return ERROR;

strcpy(Ht[i]. pstr, (5) ;

return OK;

 

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