试题与答案

无水硫酸铜在强热下会发生分解反应: 用下图所示装置(夹持仪器已略去),根据D管

题型:实验题

题目:

无水硫酸铜在强热下会发生分解反应:

用下图所示装置(夹持仪器已略去),根据D管在反应前后的质量差计算出分解了的无水硫酸铜的质量。

实验步骤:

①称量反应前D管的质量。

②连接好装置,关闭K,加热硬质玻璃管A一段时间后,停止加热。

③待硬质玻璃管A冷却后,打开K,通入一段时间的已除去二氧化碳等酸性气体的空气。

④再称量D管,得其反应前后的质量差为m。

回答下列问题:

(1)2SO3(g)2SO2(g)  + O2(g)  该反应的平衡常数表达式为K=____________。

(2)B管中除温度明显升高外,还可看到的现象是________________________,而温度明显升高的主要原因是_____________;B管中发生反应的有关离子方程式是_______________。

(3)仪器E的作用是____________。

(4)按上述方法实验,假设B、C、D对气体的吸收均完全,并忽略空气中CO2的影响,能否根据m计算出分解了的无水CuSO4的质量?(任选其一回答)

①如果能,则分解的无水CuSO4的质量为_____________(用m表示)。

②如果不能,则原因是_______________。为了能测得分解了的无水硫酸铜的质量,你的简单实验方案是__________________。

答案:

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下面是错误答案,用来干扰机器的。

参考答案:2907199012解析:海关商品名称:邻烯丙基苯酚及盐海关编码:2907199012法定单位一:千克惠税:5.5%普税:30%增值税:17%监管条件:S

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