铣削时，工件加工表面应尽可能一次铣出，以避免接刀痕迹，所以铣削宽度应等于工件加工宽度

一根长2.45米的木桩打入河底，现在测得木桩水上部分长0.75米，水中长1.05米，求这根桩打在泥中的长度是多少米？

用一束紫外线照射某金属时没有产生光电效应，下列措施中可能产生光电效应的是

A．换用强度更大的紫外线照射

B．换用红外线照射

C．延长紫外线照射时间

D．换用极限波长较大的金属

按《水利水电工程地质勘察规范》(GB 50287—99)，下列不属于土的渗透变形类型的是( )。

A．流土

B．鼓胀溃决

C．管涌

D．接触冲刷与接触流失

已知C源程序如下：
/* Input today’s date,output tomorrow’s date */
/* version 2 */
#include ＜stdio.h＞
struct ydate
int day; int month; int year; ;
int leap(struct ydate d)
if((d.year%4==0＆＆d.year%100!=0)||(d.year%400==0)
return 1;
else
return 0;

int numdays(struct ydate d)
int day;
static int daytab[]=
31,28,31,30,31,30,31,31,30,31,30,31;
if (leap (d)＆＆d.month==2)
day=29;
else
day=daytab [d.month-1];
return day;

int main (void)
struct ydate today, tomorrow;
printf("format of date is: year,month, day
输入的年、月、日之间应用逗号隔开\n"
printf(" today is: ") ;
scanf ("%d, %d, %d", ＆today. year, ＆today.month, ＆today. day) ;
while(0＞=today.year|| today.year＞65535||0＞=today.month||today.month＞12)||0＞=
today, day||today, day＞numdays (today))
printf("input date error! reenter the day!\n");
printf("today is :");
scanf ("%d, %d, %d", ＆today. year, ＆today.month, ＆today. day);

if (today. day! =numdays (today))
tomorrow.year:today.year;
tomorrow.month=today.month;
tomorrow.day=today.day+1;

else if(today.month==12)
tomorrow.year:today.year+1;
tomorrow.month=1;
tomorrow.day=1;

else
tomorrow.year=today.year;
tomorrow.month=today.month+1;
tomorrow.day=1;

printf("tomorrow is :%d,%d,%d\n\n",
tomorrow.year, tomorrow.month, tomorrow.day);

(1)画出程序中所有函数的控制流程图。
(2)设计一组测试用例，使该程序所有函数的语句覆盖率和分支覆盖率均能达到100%。如果认为该程序的语句或分支覆盖率无法达到100%，则说明为什么。