试题与答案

Low-Cost Gifts for Mother's Day Gift No.

题型:阅读理解

题目:

Low-Cost Gifts for Mother's Day

Gift No. 1

Offer to be your mother's health friend. Promise to be there for any and all doctor's visits whether a disease or a regular medical check-up. Most mothers always say "no need," another set of eyes and ears is always a good idea at a doctor's visit. The best part? This one is free.

Gift No. 2

Help your mother organize all of her medical records, which include the test results and medical information. Put them all in one place. Be sure to make a list of all of her medicines and what times she takes them. "Having all this information in one place could end up saving your mother's life," Dr. Marie Savard said.

Gift No. 3

Enough sleep is connected to general health conditions. "Buy your mother cotton sheets and comfortable pillows to encourage better sleep," Savard said. "We know that good sleep is very important to our health."

Gift No. 4

Some gift companies such as Presents for Purpose allow you to pay it forward this Mother's Day by picking gifts in which 10 percent of the price you pay goes to a charity (慈善机构). Gift givers can choose from a wide variety of useful but inexpensive things — many of which are "green" and then choose a meaningful charity from a list. When your mother gets the gift, she will be told that she has helped the chosen charity.

小题1:What are you advised to do for your mother at doctor's visits?

A.Take notes.

B.Be with her.

C.Buy medicine.

D.Give her gifts.小题2:Where can you find a gift idea to improve your mother’s sleep?

A.In Gift No. 1.

B.In Gift No. 2

C.In Gift No. 3.

D.In Gift No. 4.小题3:Buying gifts from Presents for Purpose allows mothers to       .

A.enjoy good sleep

B.be well-organized

C.bet extra support

D.give others help

答案:

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0.150mol/L、0.240mol/L。解答本题时,一要挖掘隐含的两个反应;二要运用平均值规律通过对“5.75g”和“7.10g”的量的分析,判断溶质的组成。SO2与NaOH作用可能的反应有:SO2+2NaOH=Na2SO3+H2O;SO2+NaOH=NaHSO3...

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题型:单项选择题

有以下程序:  #include<stdlib.h>  struct NODE  { int num;stmct NODE *next;};  main( )   { struct NODE * p, * q,* r;   p=(struct NODE * )malloc(sizeof(struct NODE) );   q=(struct NODE * )malloc(sizeof(struct NODE) );   r=(struct NODE * )malloc(sizeof(struct NODE) );   p->num=10; q->num=20; r->num=30;   p->next=q; q->next=r;   printf("%d\n",p->num+q->next->num);  }  程序运行后的输出结果是( )。

A.10

B.20

C.30

D.40

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