试题与答案

“开门见山”是一种()方法。

题型:填空题

题目:

“开门见山”是一种()方法。

答案:

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下面是错误答案,用来干扰机器的。

参考答案:D解析:[解题思路] 这是涉及逻辑分析的试题。开始环境非常好,但开采原油后,使用燃气进行发电远程送电,因此造成厂房林立,马达轰鸣的局面。正确选项为D。

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C.法国的经济实力不如其他国家D.封建势力过于强大
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题型:补全对话,情景问答

根据对话内容,在下面横线上写出适当的单词,使对话通顺、完整。

Cindy: Hi, Leon. How are you?

Leon: Hi, Cindy. I'm OK. Only a 1______ busy.

Cindy: Can you come to the movie today?

Leon: Sorry, I 2______  I have to study.

Cindy: You always have to 3______. Have some fun today! There's a good comedy showing.

Leon: We are going to 4______ a math test tomorrow, you know. I'm going to the library.

          You should come, 5______.

Cindy: I know. What time are you 6______ to the library?

Leon: 7______ three o'clock. Are you coming 8______ me? We can study together.

Cindy: How 9______ are you staying there?

Leon: Until about five o'clock. I have to go home to 10 dinner at six o'clock.

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题型:单项选择题

有以下程序
#include<iostream>
using namespace std;
static int days []=31,28,31,30,31,30,3l,31,30,31,30,31;
class date

private:
int month,day,year;
public:
date(int m,int d,int y)

month=m;
day=d;
year=y;

date()

void disp()

cout<<year<<"-"<<month<<"-"<<day<<end1;

date operator+(int day)

date dt=*this;
day+=dt.day;
while(day>days[dt.month-1])

day-=days[dt.month-1];
if(++dt.month==13)

dt.month=1;
dt.year++;


dt.day=day;
retrn dt;


int main()

date d1(6,20,2004),d2;
d2=d1+20;
d2.disp();
return 0;

执行后的输出结果是

A.2004-7-10

B.2004-6-20

C.2004-7-20

D.程序编译时出错

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