试题与答案

小红、小强、小林三人去完成种树任务,已知小红种2棵树的时间,小强种3棵,小林种4

题型:解答题

题目:

小红、小强、小林三人去完成种树任务,已知小红种2棵树的时间,小强种3棵,小林种4棵.他们先一起干了6天,完成全部任务的
1
2
,然后小林休息了9天,小强休息了6天,小红没休息,最后一起完成任务.所以,从开始种树算起,共用了多少天才完成了任务?小强种树占全部任务的几分之几?

答案:

假设一天小红只种2棵树,

由(2+3+4)×6=54(棵)占全部的

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2

知剩下54棵树.

在小林休息的9天中共种:

9×2+(9-6)×3

=18+9

=27(棵).

剩下的任务所需要的时间:

(54-27)÷(2+3+4)

=27÷9

=3(天)

种树需要的总天数:6+9+3=18(天),

小强种的树的数量(相对量)

3×(6+3+3)=36(棵)

36
54×2
=
1
3

答:从种树开始共用18天完成任务,小强种的树占全部任务的

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3

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