试题与答案

某纯净的天然碱可看作二氧化碳和氢氧化钠反应的产物。取6.64g天然碱用酒精灯充分

题型:计算题

题目:

纯净的天然碱可看作二氧化碳和氢氧化钠反应的产物。取6.64g天然碱用酒精灯充分加热至恒重,将生成的气体依次通过过量的浓硫酸、过量澄清石灰水后,浓硫酸增重0.9g,澄清石灰水中生成沉淀1g。

(1)充分加热后,剩余固体重          g。

(2)该天然碱成分中除含有碳酸钠外,还含有              。(填化学式)

(3)6.64g天然碱中,含碳酸钠的物质的量为               mol。

(4)该天然碱的化学式为                      

答案:

30.(8分)

[6.64-1.68-(0.9-0.18)〕/106=0.04mol

4) NaHCO3的物质的量=1.68/84=0.02mol

水的物质的量=(0.9-0.18)/18=0.04mol

该天然碱的化学式为:2Na2CO3.NaHCO3.2H2O

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