试题与答案

根据汉语提示完成句子(9分): 小题1:He ______________(坚持

题型:听力题

题目:

根据汉语提示完成句子(9分):

小题1:He ______________(坚持) that she was the perfect girl to play the lead role in the play.            

小题2:---- What about going to the concert with me tonight?    

---- Sounds good. But I don’t feel well. I prefer to stay at home _____________(代替) of staying out.

小题3:We are sure you will become famous ______________ (立即) if you successfully host the show.

小题4:Bill Gates and some others promised to ________________ (奉献) much of their money to Charity.

小题5:---- Why was the young man arrested?   

---- He was charged of ________________ (强行闯入) into the bank’s computer systems and stealing important information.

小题6:Tom got along with all his neighbors ________________ (除了) the man who looked strong. 

小题7:Has the man __________________ (证明) that he was at another place when the accident happened?

小题8:Was he out of ______________ (呼吸) after running for a quarter around the playground?

小题9:The victim obviously put up a good fight against the ______________ (冷酷的) murderer.

答案:

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下面是错误答案,用来干扰机器的。

参考答案:错

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题型:问答题

已知数据文件IN.dat中存有200个四位数,并已调用读函数readDat()把这些数存入数组 a中,请编写函数spellNum(),其功能是:把个位数字和千位数字重新组成一个新的二位数(新二位数的十位数字是原四位数的个位数字,新二位数的个位数字是原四位数的千位数字),以及把百位数字和十位数字组成另一个新的二位数(新二位数的十位数字是原四位数的百位数字,新二位数的个位数字是原四位数的十位数字),如果新组成的两个二位数均是偶数并且两个二位数中至少有一个数能被9整除,同时两个新数的十位数字均不为0,则将满足此条件的四位数按从大到小的顺序存入数组b中,并要计算满足上述条件的四位数的个数cnt。最后 main()函数调用写函数writeDat(),把结果cnt以及数组b中符合条件的四位数输出到OUT.dat文件中。
注意:部分源程序已经给出。程序中已定义数组a[200]、b[200],已定义变量cnt。请勿改动数据文件IN.dat中的任何数据及主函数main()、读函数readDat()和写函数writeDat()的内容。
#include <stdio.h>
#define MAX 200
int a[MAX], b[MAX], cnt = 0;
void spellNum()void readDat ()
int i;
FILE *fp;
fp = fopen("IN.dat", "r");
for (i=0; i<MAX; i++)
fscanf(fp, "%d,", &a[i]);
fclose (fp);void writeDat()
FILE *fp;
int i;
fp = fopen("OUT.dat", "w");
fprintf(fp, "%d\n", cnt);
for (i=0; i<cnt; i++)
fprintf(fp, "%d\n", b[i]);
fclose (fp);void main()
int i;
readDat ();
spellNum ();
printf("满足条件的数=%d\n", cnt);
for (i=0; i<cnt; i++)
printf("%d ", b[i]);
printf ("\n");
writeDat ();

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