试题与答案

“动极者,镇之以静”说明的阴阳关系是() A.对立制约 B.交感互藏 C.互根互用

题型:单项选择题

题目:

“动极者,镇之以静”说明的阴阳关系是()

A.对立制约

B.交感互藏

C.互根互用

D.相互转化

E.相互促进

答案:

参考答案:A

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题型:填空题

[说明]
下面程序定义了一个类Shape及其成员函数,然后从类Shape派生出类Point、 类Circle、类Cylinder,以及它们的成员函数。
[C++程序]
#include "iostream.h"
class Shape
public:
virtual void printShapeName() const=0; //纯虚函数
virtual float area() const return 0.0;
virtual float volumn() const return 0.0;
;
class Point: public Shape
public:
Point (float a=0, float b=0)
(x=a; y=b; )
void setPoint(float a,float b)
(x=a; y=b;)
float getX() constreturn x;
float getY() constreturn y;
virtual void printShapeName()const
(1) ;
private:
float x,y;
;
class Circle: (2)
public:
Circle(float r=0.0, float a=0.0, float b=0 .0)
:Point (a,b)
radius=r>0 r:0;
void setRadius(float r)
radius=r>0 r:0;
float getRadius () const
return radius;
virtual float area () const
return 3 .14 259*radius*radius ;
virtual void printShapeName () const
cout<<"circle:";
private :
float radius;
;
class Cylinder: (3)
public :
Cylinder(float h=0.0,float r=0.0,float x=0.0,float y=0.0)
: (4)
height=h>0 h:0;
void setHeight (float h)
height=h>0 h:0;
virtual float area () const
return (5) ;
virtual float volumn () const

float r=Circle:: getRadius ();
return 3.14159*r*r*height;

virtual void printShapeName () const
(cout<<"cylinder: " ;
private :
float height;

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