试题与答案

若NA表示阿伏加德罗常数的值，下列说法正确的是 A．0.1molNa2O2中含有

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题型：选择题

题目：

若NA表示阿伏加德罗常数的值，下列说法正确的是                   

A．0.1molNa2O2中含有的离子数为0.4NA

B．利用氧化还原反应原理制取1mol氧气，转移的电子数一定为4NA

C．7.1g氯气与足量NaOH溶液反应电子转移数为0.2NA

D．0.1mol氯气与金属铁完全反应时，转移电子数为0.2NA

答案：

答案：D

考点：阿伏加德罗定律
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题型：填空题

Part 1


Question 46-50


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[背景材料]续上题。若本施工合同为不调价估计工程量单价合同，各工作的估计工程量及承包商提交的报价清单见表3。合同规定：
1．动员预付款为合同价款的10%，从工程量达到合同价款的20%的当月到工程完工 2个月前每月平均扣除，无材料预付款；
2．保留金为合同价款的5%，从开工当月开始按工程款的10%扣除，扣完保留金后不扣；
3．合同价款按月支付，监理工程师签发月付款最低金额为50万元；
4．前8个月业主供材为0、0、30万、15万、10万、5万、10万、0
表3

工作 A B C D E F G H I J K L
估计工程量 2000m3 1500m3 3000m3 2000m2 1200m2 5000m2 4000m 5000m2 4000m2 3000m3 700m 600m2
投标报价 200元/m3 240元/m3 100元/m3 600元/m2 250元/m3 100元/m2 500元/m 60元/m2 130元/m2 150元/m3 300元/m 100元/m2
除上述三起索赔事件外承包商严格按监理批准的早时标网络计划组织施工，各项工作的作业时间也未发生变化，并假设各分项工程均衡施工，索赔金额在索赔事件结束的当月支付。

[问题二]按上述条件绘制时标网络
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