试题与答案

已知x2-y2=xy,且xy≠0,求代数式x2y-2+x-2y2的值.

题型:解答题

题目:

已知x2-y2=xy,且xy≠0,求代数式x2y-2+x-2y2的值.

答案:

∵x2-y2=xy,

∴原式=

x2
y2
+
y2
x2
=
x4+y4
x2y2

=

(x2-y2)2+2x2y2
x2y2

=

3x2y2
x2y2

=3.

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