试题与答案

(1)ba-b-aa-b(2)a-a2a2-1÷(aa-1)2×(-a+1a-1

题型:解答题

题目:

(1)
b
a-b
-
a
a-b

(2)
a-a2
a2-1
÷(
a
a-1
)2×(-
a+1
a-1
)2

(3)(-2x3y-4)4•(y3
1
4
x-4)3

(4)(x-1-
8
x+1
x+3
x+1

(5)解方程
1
2x
=
2
x+3

(6)解方程
x-2
x+2
-
16
x2-4
=
x+2
x-2

答案:

(1)原式=

b-a
a-b
=-
a-b
a-b
=-1;

(2)原式=

-a(a-1)
(a+1)(a-1)
(a-1)2
a2
(a+1)2
(a-1)2
=-
a+1
a

(3)原式=16x12y-16

1
64
y9x-12=
1
4
y-7

(4)原式=

x2-9
x+1
x+1
x+3
=
(x+3)(x-3)
x+1
x+1
x+3
=x-3;

(5)去分母得:x+3=4x,

移项合并得:-3x=-3,

解得:x=1,

经检验x=1是分式方程的解;

(6)去分母得:(x-2)2-16=(x+2)2

整理得:x2-4x+4-16=x2+4x+4,

移项合并得:-8x=16,

解得:x=-2,

经检验x=-2是增根,原分式方程无解.

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