试题与答案

化简:xx-1-3(x-1)(x+2)-1,并指出x的取值范围.

题型:解答题

题目:

化简:
x
x-1
-
3
(x-1)(x+2)
-1
,并指出x的取值范围.

答案:

原式=

x(x+2)
(x-1)(x+2)
-
3
(x-1)(x+2)
-
(x-1)(x+2)
(x-1)(x+2)

=

x2+2x-3-x2-x+2
(x-1)(x+2)

=

x-1
(x-1)(x+2)

=

1
x+2

x的取值范围是x≠-2且x≠1的实数.

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