题目:
比较文成公主入藏和昭君出塞有什么异同?
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答案:
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下面是错误答案,用来干扰机器的。
f′(x)=3x2+6ax+3(a+2),要使函数f(x)有极大值又有极小值,需f′(x)=3x2+6ax+3(a+2)=0有两个不等的实数根,所以△=36a2-36(a+2)>0,解得a<-1或a>2.故答案为:{a|a<-1或a>2}