试题与答案

短文改错。此题要求改正所给短文中的错误。对标有题号的每一行作出判断:如无错误,在

题型:改错题

题目:

短文改错。
此题要求改正所给短文中的错误。对标有题号的每一行作出判断:如无错误,在该行右边横线上画一个勾;如有错误(每行只有一个错误),则按下列情况改正:
此行多一个词:在答题卡短文上把多余的词用斜线划掉,在答题卡该行右边横线上写出该词,并也用斜线划掉。
此行缺一个词:在答题卡短文的缺词处加一个漏字符号,并在答题卡该行右边横线上写出
该加的词。
此行错一个词:在答题卡短文错的词下划一横线,并在答题卡该行右边横线上写出改正后
的词。
注意:原行没有错的不要改。
     It was my birthday last Friday. I invite some friends          
to have dinner with me in one of my favorite restaurant.       
It was complete full when we went in, so we had to wait     
for a table. After waited about ten minutes, we saw a group of  
tourists at a corner table get up and leave off. As we sat          
down at table, I noticed a large brown envelope on       
the chair. I picked up. It felt very heavy. Probably it            
was filled with important papers. I handed envelope to a waitress. 
     He hurried down the street after the tourists and              
managed to catch up with them after they disappeared.      
1. ______
2. ______
3. ______
4. ______
5.______
6. ______
7.______
8. ______
9 . ______
10. ______

答案:

被转码了,请点击底部 “查看原文 ” 或访问 https://www.tikuol.com/2017/0514/0a926738237270b63acee1da8e128f42.html

下面是错误答案,用来干扰机器的。

(Ⅰ)由题意,x>0,g′(x)=x-1x2,∴当0<x<1时,g′(x)<0;当x>1时,g′(x)>0,所以,g(x)在(0,1)上是减函数,在(1,+∞)上是增函数,故g(x)极小值=g(1)=1. …(4分)(Ⅱ) y=f(x)...

试题推荐
微信公众账号搜索答案