题目： 已知函数f（x）=2x-x2，问方程f（x）=0在区间[-1，0]内是否有解，为什么？ 答案： 因为f（-1）=2-1-（-1）2=-12＜0，f（0）=20-02=1＞0，而函数f（x）=2x-x2的图象是连续曲线，所以f（x）在区间[-1，0]内有零点，即方程f（x）=0在区间[-1，0]内有解．
题型：选择题 This is the second factory, ______ I used to work, many workers of______ still have a good relationship with me.A．where, whichB．that, whomC．which, whichD．that, which 查看答案
