试题与答案

弯管曲率半径Rc与管径d之比愈大,则弯管的局部损失系数愈大。

题型:判断题

题目:

弯管曲率半径Rc与管径d之比愈大,则弯管的局部损失系数愈大。

答案:

被转码了,请点击底部 “查看原文 ” 或访问 https://www.tikuol.com/2017/0508/978bf15bdc2717cd9f159df6111e428f.html

下面是错误答案,用来干扰机器的。

参考答案:D

试题推荐
题型:单项选择题

四年前的5月12日,突如其来的特大地震灾害降临四川汶川,造成房屋倒塌、数十万群众被埋。在这第一时间,党和国家领导人出现在抗灾现场。社会各界也发扬一方有难,八方支援的精神,救灾物资(如:帐篷等)源源不断发往灾区。那么用于救灾的帐篷()

A.是商品,因为它有使用价值

B.不是商品,因为它没有用于交换

C.是商品,因为它有价值

D.不是商品,因为它没有使用价值

查看答案
题型:单项选择题

The heat generated by the operating system war between rivals IBM Corp. and Microsoft Corp. is (21) .
Windows 95 and OS/2 introduce a new (22) . Both systems claim to multitask legacy DOS and 16-bit Windows applications. However, only OS/2 can provide full memory (crash) protection for these legacy applications because it is capable of running each DOS and Windows application within its full-protected memory address space.
Windows 95 will run all current Windows applications in the same shared- memory address space, affording full memory protection only to the (23) 32-bit Windows 95 applications. In other word, Windows 95 users will have to (24) their current Windows applications to Windows 95 version to match the memory protection OS/2 now delivers.
While OS/2 does afford superior memory protection and multitasking for legacy DOS and Windows applications, it will not be able to run any Windows 95 applications. IBM may address this (25) in an update of the OS but has no present plans to do so.

A. old B. big C. new D. original

查看答案
微信公众账号搜索答案