试题与答案

函数f（x）=logax+1＜a＞0且a≠1）在[12，1]上的最小值是1，则a

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题型：填空题

题目：

函数f（x）=logax+1＜a＞0且a≠1）在[
1
2
，1]上的最小值是1，则 a=______．

答案：

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