试题与答案

函数y=kx+b(k≠0)的图象平行于直线y=2x+3,且交y轴于点(0,-1)

题型:填空题

题目:

函数y=kx+b(k≠0)的图象平行于直线y=2x+3,且交y轴于点(0,-1),则其解析式是(    )。

答案:

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