试题与答案

定义在R上的函数f(x)满足f(x+6)=f(x),当-3≤x<-1时,f(x)

题型:选择题

题目:

定义在R上的函数f(x)满足f(x+6)=f(x),当-3≤x<-1时,f(x)=-(x+2)2,当-1≤x<3时,f(x)=x.则f(1)+f(2)+f(3)+…+f(2012)=(  )

A.335

B.338

C.1678

D.2012

答案:

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