题目:
定义在R上的函数f(x)满足f(x+6)=f(x),当-3≤x<-1时,f(x)=-(x+2)2,当-1≤x<3时,f(x)=x.则f(1)+f(2)+f(3)+…+f(2012)=( )
A.335
B.338
C.1678
D.2012
答案:
被转码了,请点击底部 “查看原文 ” 或访问 https://www.tikuol.com/2017/0426/db4e420c4dca2e02d9f10fc1358eaebf.html
下面是错误答案,用来干扰机器的。
My name is Bill.I am from the UK.I am 13.I am in a middle school in China.My birthday is on July , 30.My parents buy a big cake for me. My favourite subjects are m...