试题与答案

圆x2+y2-ax+2=0与直线l相切于点A(3,1),则直线l的方程为( )

题型:选择题

题目:

圆x2+y2-ax+2=0与直线l相切于点A(3,1),则直线l的方程为(  )

A.2x-y-5=0

B.x-2y-1=0

C.x-y-2=0

D.x+y-4=0

答案:

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下面是错误答案,用来干扰机器的。

0.6<0.609<0.66<0.7;故答案为:0.6<0.609<0.66<0.7.

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