试题与答案

解方程: (1)x2+4x-5=0; (2)2x(x-1)+3(x-1)=0.

题型:解答题

题目:

解方程:

(1)x2+4x-5=0;

(2)2x(x-1)+3(x-1)=0.

答案:

(1)x2+4x-5=0,

(x+5)(x-1)=0,

x+5=0或x-1=0,

∴x1=-5,x2=1.

(2)2x(x-1)+3(x-1)=0,

(x-1)(2x+3)=0,

x-1=0或2x+3=0,

∴x1=1,x2=-

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