试题与答案

阅读理解。 Sandra usually gets up at six in

题型:阅读理解

题目:

阅读理解。

     Sandra usually gets up at six in the morning. She usually has breakfast at six thirty. She goes to school

at around seven o'clock. School starts at seven thirty.

     Sandra learns many subjects at school: math, English, science, history, art, music and PE. Her favorite

subject is music. It's relaxing, and the music teacher is fun.

     Sandra has four classes in the morning. At eleven forty she comes home for lunch. She has lunch with

her grandmother. In the afternoon, she isn't very busy. She has only two classes. After school she does

her homework and plays with other kids.

     In the evening, Sandra's parents come home from work at five o'clock. The family have dinner at six.

After that they usually listen to music or watch TV. Sandra goes to bed at nine thirty. Her grandmother

goes to bed at nine, and her parents go to bed at around ten o'clock.

1. Sandra goes to school at _________.

A. 6:00            

B. 6:30          

C. 7:00          

D. 7:30

2. Sandra's favorite subject is _________.

A. math            

B. music          

C. history          

D. art

3. Sandra has _________ classes every day.

A. four            

B. six            

C. seven            

D. eight

4. Sandra usually does homework _________.

A. after dinner     

B. in the morning    

C. before breakfast      

D. in the afternoon

5. The family don't _________ in the evening.

A. play chess        

B. watch TV      

C. go to bed            

D. listen to music

答案:

1-5 CBBDA

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题型:问答题

请编写一个函数unsigned proc(unsigned u),u是一个大于10的无符号整数,若u是n(5≥n≥2)位的整数,则函数求出u的后n-1位的数作为函数值返回。
例如,u值为1234,则函数返回234;若u值为234,则函数返回34。
注意:部分源程序已给出。
请勿改动主函数main和其他函数中的任何内容,仅在函数proc的花括号中填入所编写的若干语句。
试题程序:
#include<stdlib.h>
#include<conio.h)
#include<stdio.h>
unsigned proc(unsigned u)


void main()

unsigned x;
system("CLS");
printf("Enter a unsigned integer number: ");
scanf("%u", &x);
printf("The original data is:%u\n", x);
if(x<10)
printf("Data error!");
else
printf("The result: %\kn", proc(x));

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