题目:
已知|x+2y-3|+(x-y+3)2=0,则(x+y)2012的值为( )
A.22011
B.-1
C.1
D.-22012
答案:
∵|x+2y-3|+(x-y+3)2=0,
∴
,x+2y-3=0① x-y+3=0②
①-②得:3y=6,即y=2,
将y=2代入①得:x+4-3=0,即x=-1,
则原式=(-1+2)2012=1.
故选C.
已知|x+2y-3|+(x-y+3)2=0,则(x+y)2012的值为( )
A.22011
B.-1
C.1
D.-22012
∵|x+2y-3|+(x-y+3)2=0,
∴
,x+2y-3=0① x-y+3=0②
①-②得:3y=6,即y=2,
将y=2代入①得:x+4-3=0,即x=-1,
则原式=(-1+2)2012=1.
故选C.