试题与答案

已知A={x|(log2x)2-log2x<0},B={x|x2-2ax+a2-

题型:解答题

题目:

已知A={x|(log2x)2-log2x<0},B={x|x2-2ax+a2-1>0},且A⊆B,求实数a的取值范围.

答案:

由题意得:A={x|0<log2x<1}={x|1<x<2}.

B={x|[x-(a-1)][x-(a+1)]>0}={x|x>a+1或x<a-1},

∵A⊆B

∴2≤a-1或a+1≤1,

∴a≥3或a≤0.

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